1function [ lambda1,lambda2,a ] = estimateH2( lambda,CX2 )
3% This function generates a 2 phase Hyper-exponential distribution
4% according to the given mean rate: lambda, and the given squared
5% coefficient of variation: CX2
8%CX2
is the squares coefficient of variation
9a = (1+sqrt((CX2-1)/(CX2+1)))/2;